# Sharingan

Author: mathforces
Problem has been solved: 11 times

Русский язык | English Language

In the equilateral triangle $ABC$, the point $X$ was chosen. $XN$, $XM$ and $XL$ are perpendiculars from point $X$ to the sides $AB$, $BC$ and $CA$, respectively. Denote by $r_{QWE}$ the radius of the inscribed circle of the triangle $QWE$. It turned out that $r_{XAN}=144$, $r_{XBM}=169$, $r_{XMC}=196$, $r_{XCL}=400$. Find $r_{XNB} + r_{XLA}$.