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Factorial Factor

Author: mathforces
Problem has been solved: 48 times

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Lin randomly selected a factor of $21! = 1 \cdot 2 \cdot 3 \cdot ... \cdot 21$. Let $ \frac{n}{m} $ be an irreducible fraction - the probability that the divisor is odd. What is $ ( |n| + 1)^2m^2 $ equal to?





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