Angle chasing
Author: daniyar
Problem has been solved: 135 times
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In quadrilateral $ABCD$, $\angle CAD = 98^{\circ}$, $\angle CBD = 82^{\circ}$, $\angle DCB = 70^{\circ}$ and $\frac{BC}{AD}=1$. FInd $\angle DCA$ in degrees.
В четырехугольнике $ABCD$, $\angle CAD = 98^{\circ}$, $\angle CBD = 82^{\circ}$, $\angle DCB = 70^{\circ}$ и $\frac{BC}{AD}=1$. Найдите $\angle DCA$ в градусах.
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